Hi
Is there a book or resource where I can find the probability of the Dealer's final hand given his up card?
e.g. if the Dealer has a 7, what is the probability of his ending up with a 17, 18, 19, 20, 21 or bust?
Hi
Is there a book or resource where I can find the probability of the Dealer's final hand given his up card?
e.g. if the Dealer has a 7, what is the probability of his ending up with a 17, 18, 19, 20, 21 or bust?
I have these numbers for infinite deck games too. However, no need to post them because they are very close to those for 8-deck games.
Page 50, Table 4.1, BJA3.
Don
In the above links, I just read this part, “when we look at the overall bust rates, we see that a single-player table sees substantially fewer dealer busts. But this has no effect on your advantage.” I guess this is not accurate. It does, especially for counters.
If the dealer does not complete her hand upon a player’s bust, more cards are saved for further playing in this current shoe; therefore, more opportunities remain for the player to exploit advantageous hands here. Right?
In the above links, I just read this part, “when we look at the overall bust rates, we see that a single-player table sees substantially fewer dealer busts. But this has no effect on your advantage.” I guess this is not accurate. It does, especially for counters.
If the dealer does not complete her hand upon a player’s bust, more cards are saved for further playing in this current shoe; therefore, more opportunities remain for the player to exploit advantageous hands here. Right?
It shouldn't have any affect on the outcome of the hand, counting or not since the hand is already over (money has been taken or paid).
Dunno how this affects overall advantage or disadvantage but possibly part of the differences between one on one play or more than one player table play.
Aceside is correct. Each time the lone player busts, the dealer doesn't complete his hand. On average, the BS player busts about 16% of the time. So, assuming a 4.5/6 game, where 234 cards will be dealt, plus a couple more after the cut card comes out, and an average of about 44 rounds, the player will break about seven times. As the dealer doesn't then take any additional cards, you save about seven cards per shoe--in effect, that much extra penetration. Not worth anything to the BS player, but something to the counter. Note, finally, that the counter breaks fewer times than the BS player, because of using indices to stand when the BS player hits and may bust.
Don
Aceside is correct. Each time the lone player busts, the dealer doesn't complete his hand. On average, the BS player busts about 16% of the time. So, assuming a 4.5/6 game, where 234 cards will be dealt, plus a couple more after the cut card comes out, and an average of about 44 rounds, the player will break about seven times. As the dealer doesn't then take any additional cards, you save about seven cards per shoe--in effect, that much extra penetration. Not worth anything to the BS player, but something to the counter. Note, finally, that the counter breaks fewer times than the BS player, because of using indices to stand when the BS player hits and may bust.
Don
Is the effect one of getting more possible opportunities during the shoe even though the cut card is in the same place?
Thanks,
Phil
Aceside is correct. Each time the lone player busts, the dealer doesn't complete his hand. On average, the BS player busts about 16% of the time. So, assuming a 4.5/6 game, where 234 cards will be dealt, plus a couple more after the cut card comes out, and an average of about 44 rounds, the player will break about seven times. As the dealer doesn't then take any additional cards, you save about seven cards per shoe--in effect, that much extra penetration. Not worth anything to the BS player, but something to the counter. Note, finally, that the counter breaks fewer times than the BS player, because of using indices to stand when the BS player hits and may bust.
Don
Is the effect one of getting more possible opportunities during the shoe even though the cut card is in the same place?
Thanks,
Phil
Yes, sure.But fewer cards per hand is the same as deeper penetration. Think about it.
Don
Aceside is correct. Each time the lone player busts, the dealer doesn't complete his hand. On average, the BS player busts about 16% of the time. So, assuming a 4.5/6 game, where 234 cards will be dealt, plus a couple more after the cut card comes out, and an average of about 44 rounds, the player will break about seven times. As the dealer doesn't then take any additional cards, you save about seven cards per shoe--in effect, that much extra penetration. Not worth anything to the BS player, but something to the counter. Note, finally, that the counter breaks fewer times than the BS player, because of using indices to stand when the BS player hits and may bust.
Don
Is the effect one of getting more possible opportunities during the shoe even though the cut card is in the same place?
Thanks,
Phil
Yes, sure.But fewer cards per hand is the same as deeper penetration. Think about it.
Don
I think I see that, thank you!
Phil
